[HAI] week3 two optimize solution remove reverse

https://leetcode.com/problems/squares-of-a-sorted-array/

lib/isPalindrome/readme.md

@@ -32,6 +32,26 @@ Constraints:
 
 ## тест кейсы
 
+```ts
+describe("isPalindrome", () => {
+  it("A man, a plan, a canal: Panama => true", () => {
+    expect(isPalindrome("A man, a plan, a canal: Panama")).toBeTruthy();
+  });
+
+  it("race a car => false", () => {
+    expect(isPalindrome("race a car")).toBeFalsy();
+  });
+
+  it(" _ => true", () => {
+    expect(isPalindrome(" ")).toBeTruthy();
+  });
+
+  it(" 0P => false", () => {
+    expect(isPalindrome("0P")).toBeFalsy();
+  });
+});
+```
+
 ## текстовое описание решения
 
 - я заведу два указателя которые поставлю в начало и в конец и буду двигаться в цикле пока эти указатели не пересекуться
@@ -101,4 +121,3 @@ function isPalindrome(s: string): boolean {
   return true;
 };
 ```
-

lib/sortedSquares/sortedSquares.ts

@@ -1,20 +1,39 @@
+// export function sortedSquares(nums: number[]): number[] {
+//   const result: number[] = [];
+//   let L = 0;
+//   let R = nums.length - 1;
+
+//   while (result.length !== nums.length) {
+//     let leftValue = Math.pow(nums[L], 2);
+//     let rightValue = Math.pow(nums[R], 2);
+
+//     if (leftValue > rightValue) {
+//       result.push(leftValue);
+//       L++;
+//     } else {
+//       result.push(rightValue);
+//       R--
+//     }
+//   }
+
+//   return result.reverse();
+// };
+
 export function sortedSquares(nums: number[]): number[] {
-  const result: number[] = [];
+  const result: number[] = Array(nums.length).fill(0);
   let L = 0;
   let R = nums.length - 1;
+  let indexResult = result.length - 1;
 
-  while (result.length !== nums.length) {
+  while (L <= R) {
     let leftValue = Math.pow(nums[L], 2);
     let rightValue = Math.pow(nums[R], 2);
+    let resultValue = leftValue > rightValue ? leftValue : rightValue;
+    leftValue > rightValue ? L++ : R--;
 
-    if (leftValue > rightValue) {
-      result.push(leftValue);
-      L++;
-    } else {
-      result.push(rightValue);
-      R--
-    }
+    result[indexResult] = resultValue;
+    indexResult--;
   }
 
-  return result.reverse();
+  return result;
 };