// You are given an array(which will have a length of at least 3, but could be very large) containing integers.
// The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer 
// N.Write a method that takes the array as an argument and returns this "outlier" N.
//
//
// [2, 4, 0, 100, 4, 11, 2602, 36] -->  11 (the only odd number)

// [160, 3, 1719, 19, 11, 13, -21] --> 160 (the only even number)
//
//


export function findOUtlier(integers: number[]): number {

  const isEvenNum = integers.filter(num => num % 2 == 0);
  const isOddNum = integers.filter(num => num % 2 != 0);

  return isEvenNum.length == 1 ? Number(isEvenNum) : Number(isOddNum);
};